Question 1046571
<pre><b>{{{matrix(1,3,
"f(x)",
""="",
system(

     matrix(2,3, x+2, if, x<0,
                  x,  if, x>=0))) }}}

First plot y = x+2 and y = x on the same set of axes:

{{{drawing(400,400,-5,5,-5,5,graph(400,400,-5,5,-5,5),
line(-7,-5,7,9),line(-7,-7,7,7) )}}}

Chop off the right part of the graph of y = x+2 at (0,2), 
and put an open circle there to show that it DOES NOT include
that point.

Chop off the left part of the graph of y = x at (0,0), 
and put a closed circle there to show that it DOES include
that point.

{{{drawing(400,400,-5,5,-5,5,graph(400,400,-5,5,-5,5),
line(-7,-5,-.15,1.85),line(0,0,7,7),
circle(0,2,.2),circle(0,0,.2),circle(0,0,.18),circle(0,0,.16),circle(0,0,.14),circle(0,0,.12),circle(0,0,.1),circle(0,0,.05),circle(0,0,.025)


 )}}}

Since all real numbers may be substituted for x and a value of y 
obtained, the domain is ALL REAL NUMBERS  {{{(matrix(1,3,-infinity,",",infinity))}}}

Since all real numbers can be obtained for y by substituting the
proper value of x, the range is also ALL REAL NUMBERS  {{{(matrix(1,3,-infinity,",",infinity))}}} 

Edwin</pre></b>