<PRE><B>Question 91217</B>
factoring a quadratic with leading coefficient greater than one
2y^2+15y+28
ac=2*28=56
b=15
Think of two numbers whose product is 56 and whose sum is 15
The numbers are 7 and 8
Replace 15y by 7y+8y to get:
2y^2+7y+8y+28
Factor to get:
y(2y+7)+4(2y+7)
Factor again to get:
(2y+7)(y+4)
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Cheers,
Stan H.</PRE>