Question 1046519
 to find a cubic equation with roots {{{x[1]=6}}},{{{x[2]=-1}}}, and {{{x[3]=3}}} use zero product formula:

{{{f(x)=(x-x[1])(x-x[2])(x-x[3])}}}


{{{f(x)=(x-6)(x-(-1))(x-3)}}}

{{{f(x)=(x-6)(x+1)(x-3)}}}

{{{f(x)=(x^2-5x-6)(x-3)}}}

{{{f(x)=x^3-8x^2+9x+18}}}


{{{ graph( 600, 600, -10, 10, -10, 25, x^3-8x^2+9x+18) }}}