Question 1046390

one third of the third of three consecutive even integers is four less than half the first .find the first integer.
<pre>Let smallest integer be S
Then 2nd and 3rd = S + 2, and S + 4, respectively
We then get: {{{(1/3)(S + 4) = (1/2)S - 4}}}
{{{(S + 4)/3 = S/2 - 4}}}
2(S + 4) = 3S - 24 ------ Multiplying by LCD, 6
2S + 8 = 3S - 24
2S - 3S = - 24 - 8
- S = - 32
S. or smallest (first) integer = {{{highlight_green(matrix(1,3, (- 32)/(- 1), or, 32))}}}
It is that SIMPLE....nothing complex!