Question 1046371
<font face="Times New Roman" size="+2">


Let *[tex \Large r] be the average speed on the return trip.  Then, since distance equals rate times time, the distance from Las Vegas to home is *[tex \Large 10r].  The average speed on the trip from home to Las Vegas is 21 mph slower, so this speed can be represented by *[tex \Large r\ -\ 21], and the distance from home to Las Vegas must be *[tex \Large 17(r\ -\ 21].  Presuming that home and Las Vegas did not move relative to one another during the time that this trip occurred, we can assert that the distance from home to Las Vegas is the same as the distance from Las Vegas to home.  Therefore, the two expressions for distance that were derived above must be equal.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 17(r\ -\ 21)\ =\ 10r]


Solve for *[tex \Large r]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

</font>