Question 1046343
.
Jack is 2 times as old as Lacy. 7 years ago the sum of their ages was 28. How old are they now?
~~~~~~~~~~~~~~~~~~~~~~~~~~


<pre>
J = 2L,       (1)   ( "Jack is 2 times as old as Lacy" )

Since "7 years ago the sum of their ages was 28", then the sum of their ages now is 28 + 7 + 7 = 42 now:

J + L = 42.   (2) 

Substitute (1) into (2. You will get

2L + l = 42,

3L = 42,

L = {{{42/3}}} = 14.

<U>Answer</U>.  Lacy is 14 years now. Jack is 14*2 = 28 years old now.
</pre>

For many other solved age problems see the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Age-problems-and-their-solutions.lesson>Age problems and their solutions</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Fresh-formulation-of-a-traditional-age-problem.lesson>A fresh formulation of a traditional age problem</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Really-intricate-age-word-problem.lesson>Really intricate age word problem</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/age/Selected-age-word-problems-from-the-archive.lesson>Selected age word problems from the archive</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/age/Age-problem-for-the-day-of-April-1.lesson>Age problem for the day of April, 1</A> 

in this site.


Read them and become an expert in solution age problems.


Also, you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.

which includes many other word problems and many other interesting and useful things.