Question 1046315

let's number be {{{x}}}
Quotient of two and a number is:{{{2/x}}} 
it is equal to the sum of the number {{{x}}} and its reciprocal {{{1/x}}}:

{{{2/x=x+1/x}}}

{{{2/x-x-1/x=0}}}

{{{(2/x-1/x)-x=0}}}

{{{1/x-x=0}}}........both sides multiply by {{{x}}}

{{{(1/x)x-x*x=0*x}}}

{{{(1/cross(x))cross(x)-x^2=0}}}

{{{1-x^2=0}}}...factor

{{{(1-x)(1+x)=0}}}

solutions:

if {{{(1-x)=0}}}->{{{x=1}}}

if {{{(1+x)=0}}}->{{{x=-1}}}


so, your number could be {{{1}}} or {{{-1}}}