Question 1046264
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what is the minimum value of 2sin^2(x)+3cos^2(x)
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2sin^2(x)+3cos^2(x) = ( 2sin^2(x)+2cos^2(x) ) + cos^2(x) = 1 + cos^2(x).


The minimum value is 1.  It is achieved when cos(x) = 0, i.e. at x = {{{pi/2 + k*pi}}}, where k is any integer.