Question 91152
243/64 = 16(3/4)^n-1
Divide both sides by 16 to get:
(3/4)^(n-1) = 243/[64*16]
Take the log of both sides to get:
(n-1)log(3/4) = log243-[log64+log16]
(n-1)log(3/4) = -0.624693683...
Divide both sides by log(3/4) to get:
n-1 = 5
n = 6
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Cheers,
Stan H.