Question 1046215
<font face="Times New Roman" size="+2">


The graph of the quadratic function:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \rho(x)\ =\ ax^2\ +\ bx\ +\ c]


opens upward and has a minimum value if the lead coefficient, *[tex \Large a] is greater than zero, and opens downward and has a maximum value if the lead coefficient is negative.


The value of the independent variable, *[tex \Large x] that produces the minimum or maximum value is *[tex \Large x_v\ =\ -\frac{b}{2a}].  And the actual minimum or maximum value is the value of the function evaluated at *[tex \Large x_v].  That is to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \rho(x_v)\ =\ a(x_v)^2\ +\ b(x_v)\ +\ c]


All you have to do is the arithmetic with your given coefficients.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

</font>