Question 1046208
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Natural numbers: {{{sqrt(16)}}} and {{{2}}}


Note: this is the list of positive whole numbers. Also, {{{sqrt(16) = 4}}}

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Whole numbers: {{{sqrt(16)}}}, {{{0}}} and {{{2}}}


Note: This is the list of values that don't have decimal parts and are not negative. Also, {{{sqrt(16) = 4}}}


Another side note: The set of whole numbers is basically the set of natural numbers but we include 0. 

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Negative numbers: {{{-3.5}}}, {{{-3.55555}}}, {{{-4}}}, {{{-1&1/3}}}, {{{-sqrt(5)}}}


Note: Simply list any number that has a negative in front of it. Keep in mind that |-2.8| = 2.8 is positive in the end. Which means it's not part of the list.  

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Integers: {{{sqrt(16)}}}, {{{-4}}}, {{{0}}}, {{{2}}}


Note: This list consists of whole numbers that are positive, negative or 0. {{{sqrt(16)=4}}}

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Rational: {{{-3.5}}}, {{{sqrt(16)}}}, {{{-3.55555}}}, {{{-4}}}, {{{2/3}}}, {{{0}}}, {{{2}}}, {{{-1&1/3}}}, {{{abs(-2.8)}}}


Notice how every value in that list above can be written as a fraction of integers
{{{-3.5 = -35/10}}}
{{{sqrt(16) = 4 = 4/1}}}
{{{-3.55555 = -32/9}}} assuming the '5's go on forever
{{{-4 = -4/1}}}
{{{0 = 0/1}}}
{{{2 = 2/1}}}
{{{-1&1/3 = -4/3}}}
{{{abs(-2.8) = 2.8 = 28/10}}}


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Irrational: {{{sqrt(3)}}}, {{{pi}}} and {{{-sqrt(5)}}}


Every value in this list is a number that CANNOT be written as a fraction of integers. If a number is rational, then it is not irrational. If a number is irrational, then it's not rational. 

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