Question 1046164
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Corey is 138 miles away from Paul. They are traveling towards each other. If Paul travels 7 mph faster than Corey and they meet after 6 hours, how fast was each traveling?
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Let x = Corey's speed in mph. Then Paul's speed is (x+7) mph. 

Then you have the "distance" equation

6x + 6(x+7) = 138.

Solve it for x.
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