Question 91137
Factoring a quadratic with leading coefficient greater than one-- can your calculators answer these problems, so far answers are all wrong
10w^2+11w-6
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The following is called The AC-Method:
Think of two numbers whose product = ac = 10*-6 = -60
and whose sum = b = 11
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The numbers are 15 and -4
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In place of 11w in the original problem put 15w-4w, as follows:
10w^2+15w-4w-6
Factor the 1st two and the last two terms separately:
5w(2w+3)-2(2w+3)
Factor again to get the final answer:
(2w+3)(5w-2)
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Cheers,
Stan H.