Question 1046104
Let x = (1-t)
Then:
g(x) = 3x^2 - 2x + 1 
 {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
 {{{x = (2 +- sqrt(4 - 12 ))/(6) }}}
x = {{{(2 +- sqrt(-8))/6}}}
x = 1/3 ± 2i√2
and
1-t = 1/3 ± 2i√2
2/3 ± 2i√2 = t
Check All work
Note:
3x^2 - 2x - 1 = (3x + 1)(x-1)  Much easier to solve