Question 1046026
{{{16x<=32}}}, coefficient on x is positive.  Multiplying both sides by {{{1/16}}} makes no change regarding order.


{{{16x(1/16)<=32(1/16)}}}
{{{x<=2}}}




{{{-5x<=-40}}}
Where is  {{{-40}}} on a real number line?  Some fourty units to the left of 0.
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Where is  {{{-5x}}} on a real number line according to your given inequality?   Some number of units, variable, to the LEFT of the {{{-40}}}; so the order of the two members are now clear.  Make a number line and label all the parts and this helps to see all this.   
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Multiplicative inverse of  {{{-5}}} is  {{{-1/5}}}.
Now, refer again to the number line if this will help.
What happens to order when multiplying  {{{-5x(-1/5)}}} and the {{{-40(-1/5)}}}?


The order of the <b>resulting</b> members is reversed.
{{{-5x(-1/5)>=-40(-1/5)}}}
{{{x>=8}}}