<PRE><B>Question 1045888</B>
Mariana averaged 83 on her first three history exams.
 The first score was 93. 
The second score was 44 less than the third score.
 What did she score on the second and third&amp;#8203; exams? 
:
let x = the score on the 3rd exam
then
(x-44) = the score on the 2nd
:
{{{(93 + (x-44) + x)/3}}} = 83
multiply both sides by 3, combine like terms
93 - 44 + x + x = 3(83)
49 + 2x = 249
2x = 249 - 49
2x = 200
x = 100 her score on the 3rd exam
then
100 - 44 = 56 on the 2nd exam
:
;
Check
{{{(93+56+100)/3}}} = 83</PRE>