Question 1045863
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Multiply the second equation by 16


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 32x\ -\ 16y^2\ =\ -64]


Add the two equations, term by term, to get:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x^2\ +\ 32x\ =\ 0]


Solve for *[tex \Large x]


Substitute the roots for x in either equation and then solve for y.  Discard one of the x-values because you get a complex number result for y.  The remaining value of x paired with either of the two real roots for y are your two intersection points.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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