Question 1045783
Let {{{ W }}} = the width of the room in meters
{{{ W + 6 }}} = the length of the room in meters
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The formula for perimeter {{{ P }}} is:
{{{ P = 2W + 2L }}}
and, for this problem,
{{{ L = W + 6 }}} and
{{{ P = 24 }}}
{{{ P = 2W + 2*( W + 6 ) }}}
{{{ 24 = 2W + 2W + 12 }}}
{{{ 4W = 12 }}}
{{{ W = 3 }}}
and
{{{ W + 6 = 3 + 6 }}}
{{{ W + 6 = 9 }}}
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the dimensions of the room are 3 x 9 
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check:
{{{ P = 2W + 2L }}}
{{{ P = 2*3 + 2*9 }}}
{{{ P = 6 + 18 }}}
{{{ P = 24 }}}
OK