Question 1045756
h for hypotenuse
y for height
x for length


AREA:
{{{(1/2)xy=450sqrt(3)}}}


Either leg,
{{{x=h/2}}}


The triangle is a RIGHT Triangle.
{{{x^2+y^2=h^2}}}



System of Equations:
{{{system((1/2)xy=450sqrt(3),h=2x,x^2+y^2=h^2)}}}, having one modification done already.


Another modification,
{{{system(xy=900sqrt(3),h=2x,x^2+y^2=h^2)}}}
Take the rest of the process; a few or several algebra steps.  The obvious first step is substitute for h in the Pythagorean Theorem relationship equation.