Question 1045630
Are you trying to fill a table like this?
<pre>
<u>x</u>   <u>y</u>
?   0
0   ?
1   ?
?   2
</pre>


Simplify the given equation first.
{{{2x-y=3}}}



Solve for x in terms of y:
{{{2x=3+y}}}
{{{x=(3+y)/2}}}
Use each given y value and evaluate corresponding x value.



Solve for y in terms of x:
{{{-y=3-2x}}}
{{{y=-3+2x}}}
{{{y=2x-3}}}
Use each given x value and evaluate corresponding y value.