Question 1045580


{{{y=(x+4)/x}}}

to find inverse {{{y^-1}}}, first swap {{{x}}} and {{{y}}}

{{{x=(y+4)/y}}}....solve for {{{y}}}

{{{x= y/y+4/y}}}

{{{x= 1+4/y}}}

{{{x-1=4/y}}}

{{{y(x-1)=4}}}

{{{y=4/(x-1)}}}

so, inverse is:

{{{y^(-1)=4/(x-1)}}}


{{{ graph( 600, 600, -10, 10, -10, 10, (x+4)/x, 4/(x-1)) }}}