Question 90969
Hello,
      First of all, factorise the expressions wherever possible and then start simplifying by cancelling/factoring. Now coming to the problem, you can factorise all the expressions (numerators & denominators).  I think you know how to factorise. 
    
      {{{(x^2-6x+8)/(x^2-17x+70)}}}*{{{(x^2-15x+56)/(x^2-15x+44)}}} =  {{{(x-4)(x-2)/(x-10)(x-7)}}}*{{{((x-8)(x-7))/((x-11)(x-4))}}} = {{{cross((x-4))(x-2)/(x-10)cross((x-7))}}}*{{{(x-8)cross((x-7))/(x-11)cross((x-4))}}} = {{{(x-2)(x-8)/(x-10)(x-11)  =  (x^2-10x+16)/(x^2-21x+110)}}}  Answer.

      I think this is clear to you now. If not, feel free to contact me anytime.  All the best.

gsm