Question 1045468
Due to inclement weather, the pilot of the plane slows down the plane's regular flying rate by 25%. This results an additional 1.5hours in covering 3000km distance to its regular time required for the trip. Find the regular rate of the trip
<pre>Let regular rate be S
Then reduced rate during trip = .75S
Time to cover 3,000 km at regular rate: {{{matrix(1,1, "3,000"/S)}}}
Time to cover 3,000 km at reduced rate: {{{matrix(1,1, "3,000"/(.75S))}}}
We then get the following TIME equation: {{{matrix(1,1, "3,000"/S = "3,000"/(.75S) - 1.5)}}}
3,000(.75) = 3,000 – 1.5(.75S) -------- Multiplying by LCD, .75S
2,250 = 3,000 – 1.125S
1.125S = 3,000 – 2,250
1.125S = 750
S, or regular rate = {{{750/1.125}}} = {{{highlight_green(matrix(1,2, 666&2/3, "km/h"))}}}
It is that SIMPLE, with just ONE (1) variable: the one you're looking for!