Question 1045466
"x", not "X".


{{{3^(2x-2)=root(3,2)}}}
{{{log((3^(2x-2)))=log((2^(1/3)))}}}
{{{(2x-2)*log((3))=(1/3)*log((2))}}}
{{{(x-1)*log((3))=(1/6)*log((2))}}}
{{{(x-1)=((1/6)*log((2)))/log((3))}}}
{{{x=1+((1/6)*log((2))/log((3)))}}}


Not really finished.  You decide if you need a result combined as a single rational expression or not; you choose which base of the logarithm you want.  Typically Natural Log, or Common Log.