Question 1045373
the standard slope-intercept form for an equation of a line is {{{y = highlight_green(m)x + highlight(b)}}}  
where m is the slope and b the y-intercept.
  y = (-1/3)x + 4  Slope is (-1/3)
Line perpendicular to that Line is 3 (negative reciprocal)
***Using point-slope form, {{{y - y[1] = highlight_green(m)(x - x[1])}}}
y - 2 = 3(x+4)
y = 3x + 14
{{{drawing(300,300,    -20,20,-20,20,  
 grid(1),


graph( 300, 300, -20,20,-20,20,0, -x/3 + 4, 3x + 14))}}}