Question 1045311
X hits----0.3
X misses-0.7------Y hits 0.6
-------------------Y misses 0.4----X hits 0.4
-------------------X misses 0.6---Y hits 0.4
X hits Y:0.3
Y hits X:0.7*0.6 (0.42)
X hits: 0.3*0.4*0.4=0.048
Y hits: 0.7*0.4*0.6*0.4=0.0672
Y hits on the first attempt: 0.42
Y hits on the second attempt 0.0672
Answer is Probability of 0.4872 that Y will hit X.
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Probability X will hit Y is 0.3+0.7*0.4*0.4=0.412
The remainder of 0.111 is that neither hits the other.