Question 1045202
here's the graph.


<img src = "http://theo.x10hosting.com/2016/082601.jpg" alt="$$$" </>


the domain is all real values of x.


the range is all real values of y >= 1.


you can't see it on the graph because the values of x extend all the way to plus and minus infinity.


similarly, the values of y extend all the way to plus infinity.


a simple test is to take a very high value of x and a vary low value of x, such as plus or minus 1000000.


use your calculator to find the value of y when y = x^2 + 1.


for 1000000, the value of y will be 1 * 10^12 based on what the calculator can show.


for -1000000, the value of y will be 1 * 10^12 again.


you made x very very large in a negative and positive direction and the value of y became very very large in a positive direction.


all values of x are in the domain because there is no value of x that's not real.


based on the equation, y can be any value of y that's positive and greaer than or equal to 1.


when x = 0, y = 1


y is positive when x gets greater than 0 in a positive or negative direction.


here's a tutorial that might help.


if you have any more questions on this topic, or have another specific problem regarding it that you are struggling with, send me an email.


<a href = "http://www.intmath.com/functions-and-graphs/2a-domain-and-range.php" target = "_blank">http://www.intmath.com/functions-and-graphs/2a-domain-and-range.php</a>


be aware that most of the time they are talking about functions, which are subsets of equation.


if there is only value of y for each and every value of x, then you have a function.


if there can be more than one value of y for any value of x, then you have a relation.


the equation you gave me is a function.


here's a graph of an equation that is a rerlation and not a function.


the equation is y^2 = x


solve for y in that equation and you will get y = plus or minus square root of (x).


the domain is all real values of x that are greater than or equal to 0.


those values of x will create real values of y.


negative values of x will not create real values of y because the square root of a negative number is not real.


here's the graph:


<img src="http://theo.x10hosting.com/2016/082602.jpg" alt="$$$" </>



the domain is all real value of x >= 0.


the range is all real values of y.


you can see that the graph doesn't show anything for any values of x < 0.


this is because the graph will only show the real values of y.


any value of x > 0 will result in a real value of plus or minus y.


this equaton is not a function because there are more than one possible value of y for any one distinct value of x.


for erxample, when x = 4, y = plus or minus 2.