Question 1045139
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5 oz. of a 2% alcohol solution was mixed with 11 oz. of a 66% alcohol solution. Find the concentration of the new mixture
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The amount of the pure alcohol in the mixture is  (0.02*5 + 0.66*11) oz.

The volume of the mixture is (5 + 11) oz.

The concentration of the mixture is {{{((0.02*5 + 0.66*11)/(5 + 11))*100}}} percents.

Calculate.
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