Question 1045092
Let {{{ s }}} = the speed of Adam's bus in mi/hr
{{{ s - 20 }}} = the speed of Mike's bus in mi/hr
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Since they are travelling in opposite directions, you
can think of this as one of them standing still and
the other covering the {{{ 270 }}} miles at the sum
of their speeds
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{{{ 270 = ( s + s - 20 )*3 }}}
{{{ 270 = ( 2s - 20 )*3 }}}
{{{ 270 = 6s - 60 }}}
{{{ 6s = 330 }}}
{{{ s = 55 }}}
and
{{{ s - 20 = 35 }}}
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Adam's speed is 55 mi/hr
Mike's speed is 35 mi/hr
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check answer:
Adam's equation:
{{{ d[1] = 55*3 }}}
{{{ d[1] = 165 }}} mi
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Mike's equation:
{{{ d[2] = 35*3 }}}
{{{ d[2] = 105 }}} mi
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{{{ d[1] + d[2] = 270 }}}
{{{ 165 + 105 = 270 }}}
{{{ 270 = 270 }}}
OK