Question 1045078
Let the 3 consecutive odd numbers be
{{{ n }}}, {{{ n + 2 }}}, and {{{ n + 4 }}}
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{{{ n*( n + 2 ) = ( n + 4 )^2 - 34  }}}
{{{ n^2 + 2n = n^2 + 8n + 16 - 34 }}}
{{{ 2n = 8n - 18 }}}
{{{ 6n = 18 }}}
{{{ n = 3 }}}
and
{{{ n + 2 = 5 }}}
{{{ n + 4 = 7 }}}
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The numbers are 3, 5, and 7
check:
{{{ n*( n + 2 ) = ( n + 4 )^2 - 34  }}}
{{{ 3*( 3 + 2 ) = ( 3 + 4 )^2 - 34  }}}
{{{ 3*5 = 7^2 - 34 }}}
{{{ 15 =49 - 34 }}}
{{{ 15 = 15 }}}
OK