Question 1044942
f(x) = (x+5)^2  * (x-2)^2
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when x = 0, f(x) is the y intercept
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f(x) = 5^2 * (-2)^2 = 100
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when f(x) = 0 we have an x intercept
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we have 2 x-intercepts, x = -5, x = 2
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here is the graph
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{{{ graph( 300, 200, -8, 5, 0, 400, (x+5)^2  * (x-2)^2) }}}
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a) y intercept is 100, x intercepts are -5 and 2
b) f(x) touches the x axis at (-5,0) and (2,0) since f(x) is always > or = 0
c) see graph above
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