Question 90971
{{{((z^2+11z+18)/(z^2+12z+27))/((z^2+2z)/(z^2-6z-27))}}}



{{{((z^2+11z+18)/(z^2+12z+27))*((z^2-6z-27)/(z^2+2z))}}} Multiply the first fraction by the reciprocal of the second



{{{((z+9)(z+2)/(z^2+12z+27))*((z^2-6z-27)/(z^2+2z))}}} Factor the first numerator (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)


{{{((z+9)(z+2)/(z+9)(z+3))*((z^2-6z-27)/(z^2+2z))}}} Factor the first denominator


{{{((z+9)(z+2)/(z+9)(z+3))*((z-9)(z+3)/(z^2+2z))}}} Factor the second numerator



{{{((z+9)(z+2)/(z+9)(z+3))*((z-9)(z+3)/z(z+2))}}} Factor the second denominator



{{{(cross((z+9))cross((z+2))/cross((z+9))cross((z+3)))*((z-9)cross((z+3))/(z*cross((z+2))))}}} Cancel like terms


{{{(z-9)/z}}} Simplify