Question 1044855
If 4A = I and 8A = U, show algebraically the number of I's 
needed to equal one U.
<pre>
Let n = the number of I's needed to equal one U.

Then

nI = U

Substitute 4A for I and substitute 8A for U

n(4A) = 8A

Solve for n:

Simplifying:

4nA = 8A

Divide both sides by 4A

{{{4nA/(4A)}}}{{{""=""}}}{{{8A/(4A)}}}

{{{n}}}{{{""=""}}}{{{2}}}

So we need 2 I's to equal one U.

Edwin</pre>