Question 1044832
It is E.  Here is why.
Write the numerator as 9-(1/x^2).  Common denominator of x^2 and get (9x^2-1)/x^2 and write it as 
(3x+1)(3x-1)/x^2, a difference of squares.  This is the numerator.
The denominator is 3+(1/x). That is (3x+1)/x
We cancel a (3x+1) in both and an x in both.
That leaves (3x-1)/x, or E.
Sometimes you want negative exponents, other times you want to write them as fractions.  Here, the latter works better.