<PRE><B>Question 90853</B>
The given equations are:  


{{{ 2 + (x/7) = (y/4) }}}


{{{3 + (y/5) = (x/3) }}}


Taking LCM, this can be written as:



{{{((14 + x)/7) = (y/4)}}} 


{{{(15 + y)/5) = (x/3)}}} 


Now cross multiplying and writing x and y terms on one side, we get: 


56 + 4x = 7y  ----------(1)


45 - 5x = - 3y ---------(2) 



Now lets solve both the equations simultaneously, Multiply eqn (1) by 3 and (2) by 7. 


We get:


168 + 12x = 21y

315 - 35x = - 21y

on solving them we get -23x = -483

==&gt; x = 21

substituting the value of x we get the value of y

==&gt; y = 20


thus the solution











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