Question 1044797
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ ab^x]


Since *[tex \Large (1,1)] is on the graph, 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ ab\ =\ 1]


Which is to say


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ b\ =\ \frac{1}{a}]


Then, since *[tex \Large (2,3.5)] is on the graph:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ ab^2\ =\ 3.5]


Substitute *[tex \Large \frac{1}{a}] for b:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1}{a}\ =\ 3.5]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ =\ \frac{2}{7}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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