Question 1044766
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Kindly help me solving it i tried my best but I couldn't 
lim    (10^x-5^x-2^x+1)/x^2 is equal to 
x-->0
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<pre>
{{{(10^x-5^x-2^x+1)/x^2}}} = {{{((1-5^x)*(1-2^x))/x^2}}} = {{{(1-5^x)/x}}}.{{{(1-2^x)/x}}}.

Therefore,

lim   ( (10^x-5^x-2^x+1)/x^2)  is equal to  ln(5) * ln(2).
x&#10145;0 

</pre>