Question 1044769

X+y+z=6
X-y+z=2
2x+y-z=1
<pre>x + y + z = 6 -------- Considering X is same as x ------- eq (i)
x - y + z = 2 -------- Considering X is same as x ------- eq (ii)
2x + y - z = 1 ------- eq (iii)
2y = 4 ------ Subtracting eq (ii) from eq (i)
y = {{{4/2}}}, or 2

3x = 3 ------ Adding eqs (ii) & (iii)
x = {{{3/3}}}, or 1

1 + 2 + z = 6 ------- Substituting 1 for x, and 2 for y in eq (i)
3 + z = 6
z = 6 - 3, or 3
Solution set: {{{highlight_green(system(x = 1, y = 2, z = 3))}}}