Question 1044784
I need help i don't know how to solve Problem Solving like this :(
The base of an isosceles triangle is 8 m more than its altitude. If its area is 192 m^2, find the length of its sides.
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Area = b*h/2 = 192
b*h = 384
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Find a pair of factors of 384 that differ by 8
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b = 24
h = 16
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The altitude forms 2 right triangles with sides of 12 & 16
The 2 equal sides are sqrt(12^2 + 16^2) = 20
--> sides are 20, 20 & 24