Question 90770


     Find an equation for the line with y-intercept 3 that is perpendicular to the line y=2/3x-4.


      The required eq'n is y = mx+c 

         y intercept = c = 3

         product of slopes = -1

            m.M = -1
              m = -1/M = -1/2/3 = -3/2

           The eq'n becomes y = -3x/2+3

                            2y = -3x+6    (multiply by 2 throughout)

                          3x+2y = 6