Question 1044685
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When the eggs in a basket are grouped into 2,3, or 5 , there is always one extra. 
What is the least number of eggs for this grouping to be done?
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<pre>
Let N be the unknown number of eggs.


Let us take one egg off. Then we will have N-1 eggs, and N-1 will be multiple of 2, 3, and 5.

The least such a multiple is 2*3*5 = 30.

Hence, N-1 = 30.

Then N = 31.
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Solved.


See similar problem in the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/divisibility/lessons/The-number-that-leaves-a-remainder-1-when-divided-by-2-by-3-by-4-by-5-and-so-on-until-9.lesson>The number that leaves a remainder 1 when divided by 2, by 3, by 4, by 5 and so on until 9</A>

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