Question 1044677
lim (1/x)log(1-x/2)
x->0

= lim((log(1-x/2))/x)
  x->0
Then we can use L'Hopital's Rule!!
= lim(d/dx log(1-x/2)) <-- because d/dx x = 1
  x->0
= lim(1/((2-x)(ln 10)))
  x->0
= 1/(2 ln 10) 
Therefore, none of them is the answer.
:D ~Max who love Maths.