<PRE><B>Question 90829</B>


      Solve the system by addition.
5x – 3y = 13
4x – 3y = 11

          5x- 3y = 13.........(1)

          4x - 3y = 11........(2)

       multiply (1)  by -1  and add to (2)

         -5x+3y = -13
          4x-3y = 11

          -x = -2  (cancelling 3y  &amp;-3y) 
            x = 2 

       substituting for x in (1) 

              5*2 - 3y = 13
              10 - 3y =13
                10-13 = 3y
                    3y = -3  or y =-1

     The required solution is x = 2   and  y = -1</PRE>