Question 1044581
Hi tutors here at algebra.com you've made my day happy. I just wanna ask this problem:

" A car travels 60 miles in the same time that a car travelling 10 miles per hour faster travels 90 miles. What is the rate of each car?"

Thanks for answering this problem 
<pre>Let speed (rate) of slower car be S
Then speed (rate) of faster car = S + 10
Time slower car takes to cover 60 miles: {{{60/S}}}
Time faster car takes to cover 90 miles: {{{90/(S + 10)}}}
We then get the following TIME equation: {{{60/S = 90/(S + 10)}}}
90S = 60(S + 10)------ Cross-multiplying
90S = 60S + 600
90S - 60S = 600
30S = 600
S, or speed (rate) of slower car = {{{600/30}}}, or {{{highlight_green(matrix(1,2, 20, mph))}}} 
Add 10 to this speed (rate) to get speed (rate) of faster car.