Question 1044647
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Please show me how to solve :  n + 3  over 5  =  n - 1 over 2
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<pre>
{{{(n+3)/5}}} = {{{(n-1)/2}}}.

Multiply both sides by 10 (which is the Least Common Denominator) to rid of the denominators. You will get

2*(n+3) = 5*(n-1).

Simplify:

2n + 6 = 5n - 5,

6 + 5 = 5n - 2n,

11 = 3n,

n = {{{11/3}}}.

<U>Check</U>.  {{{(n+3)/5}}} = {{{((11/3 + 3))/5}}} = {{{((11/3 + 9/3))/5}}} = {{{20/(5*3)}}} = {{{20/15}}} = {{{4/3}}}.

{{{(n-1)/2}}} = {{{((11/3-1))/2}}} = {{{((11/3-3/3))/2}}} = {{{((8/3))/2}}} = {{{8/(3*2)}}} = {{{4/3}}}.   OK, correct.

<U>Answer</U>.  n = {{{11/3}}}.
</pre>