Question 90835

 Write the equation of the line with slope -1/2 (fraction) and y-intercept (0, 3). Then graph the line.

 
       The eq'n to the line will be of the form y = mx+c 
 
       where m = slope of the line = -1/2

        c = y -intercept = 3

         Therefore the eq'n becomes , y = -1/2.x+3

            multiply by 2 throughout

                        2y = -x+6

                    2y+x = 6  is the required eq'n  



     To draw the graph   y = -x/2+3

      {{{ graph( 300, 200, -6, 5, -10, 10, -x/2+3) }}}