Question 1044636
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 the radius (R) and the center (C) of this circle x^2+y^2+6x-4y+3=0 are  ? 
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Complete the square separately in "x" and "y":

{{{x^2+y^2+6x-4y+3}}} = 0   --->

({{{x^2+6x}}} + __) - __ + ({{{y^2-4y}}} + __) - __ + 3 = 0,

{{{(x^2 +6x +9) - 9 +(y^2-4y+4) - 4 + 3}}} = 0,

{{{(x+3)^2 -9 + (y-2)^2 - 4 + 3}}} = 0,

{{{(x+3)^2 + (y-2)^2}}} = 9 + 4 - 3,

{{{(x+3)^2 + (y-2)^2}}} = 10.

The circle with the center at  (-3,2)  of the radius  {{{sqrt(10)}}}.
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