Question 1044612
{(x^2-5x+6)(x^2-3x+2)}/x^3-3x^2+4 =
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{(x-6)(x+1)(x-1)(x-2)}/(x+1)(x-2)^2 =
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{(x-6)(x-1)} / (x-2)
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There are two limits
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limit as x--->2 from the right is -infinity
limit as x--->2 from the left is infinity
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you can see this from the plot of {(x-6)(x-1)} / (x-2)
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the curves are asymptotic to x = 2 
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{{{ graph( 300, 200, -15, 20, -40, 40, ((x-6)(x-1))/(x-2)) }}}
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