Question 1044537
the point of intersection of the line 2x-y=4 and the parabola y=x^2-3 is ?



y = 2x -4

2x-4 = x^2 -3

x^2-2x+1 = 0

(x-1)^2 = 0

x =1 

y = -2

Answer: Point is (1,-2)

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