Question 1044522
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Good evening who can me explain step by step how to solve following equation?
tan^2(2x+pi/4)-1=0
Thank you in advance RB
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<pre>
{{{tan^2(2x+pi/4)-1}}} = 0  --->

{{{tan^2(2x+pi/4)}}} = 1  --->

{{{tan(2x+pi/4)}}} = +/-1  --->

{{{2x + pi/4}}} = {{{pi/4 + k*(pi/2)}}}, where k is any integer --->

2x = {{{(k*pi)/2}}}, where k is any integer  --->

x = {{{(k*pi)/4}}}, where k is any integer.

<U>Answer</U>.  x = {{{(k*pi)/4}}}, where k is any integer.
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